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Oracle Database SQL Sample Questions (Q273-Q278):

NEW QUESTION # 273
Examine the structure of the EMPLOYEES table. (Choose the best answer.)

You must display the details of employees who have manager with MANAGER_ID 100, who were hired in the past 6 months and who have salaries greater than 10000.

A. (SELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000UNION ALLSELECT last_name, hire_date, salaryFROM employeesWHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id = 100))UNIONSELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE -180;
B. SELECT last_name, hire_date, salaryFROM employeesWHERE manager_id
(SELECT employee_id FROM employees WHERE employee_id = 100)UNION
ALL(SELECT last_name, hire_date, salaryFROM employeesWHERE hire_date >
SYSDATE -180INTERSECTSELECT last_name, hire_date, salaryFROM
employeesWHERE salary > 10000);
C. SELECT last_name, hire_date, salaryFROM employeesWHERE manager_id
(SELECT employee_id FROM employees WHERE employee_id = '100')UNIONSELECT last_name, hire_date, salaryFROM employeesWHERE hire_date > SYSDATE -
1 80INTERSECTSELECT last_name, hire_date, salaryFROM employeesWHERE salary >
1 0000;
D. SELECT last_name, hire_date, salaryFROM employeesWHERE salary > 10000UNION ALL SELECT last_name, hire_date, salaryFROM employeesWHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id
100)INETRSECTSELECT last_name, hire_date, salaryFROM employees WHERE
hire_date > SYSDATE- 180;

Answer: C

NEW QUESTION # 274
You execute these commands:
SQL> DEFINE hiredate = '01-APR -2011';
SQL> SELECT employee_id, first_name, salary FROM employees WHERE hire date > &hiredate AND manager_id >&mgr_id;
For which substitution variables will you be prompted?

A. only &mgr_id
B. only &hiredate
C. none
D. &hiredate and &mgr_id

Answer: A

NEW QUESTION # 275
Examine the description of the EMPLOYEES table:

NLS_DATE FORMAT is DD-MON-RR.
Which two queries will execute successfully?

A. SELECT dept_ id, AVG(MAX(salary)) FROM employees GROUP BY dept_id, salary;
B. SELECT dept id, MAX (SUM(salary)) FROM employees GROUP BY dept_id;
C. SELECT dept_ id, AVG (MAX(salary)) FROM employees GROUP By dept_id HAVING hire_date> ' O1-JAN-19';
D. SELECT AVG(MAX(salary)) FROM employees GROUP BY salary;
E. SELECT dept_ iD, sum(salary) FROM employees WHERE hire_date > '01-JAN-9' GROUP BY dept_id;

Answer: E

Explanation:
In Oracle SQL, aggregation functions such as AVG and MAX cannot be nested directly inside each other and must be used in conjunction with GROUP BY on the column(s) that are not included in the aggregate function.
Also, the HAVING clause filters groups after aggregation is applied.
A). This query will not execute successfully because it improperly nests MAX inside AVG. Oracle SQL does not allow this type of nested aggregation without a subquery.
B). This query will not execute successfully for the same reason as A, it improperly nests MAX inside AVG.
C). Similar to A and B, this query improperly nests SUM inside MAX, which is not allowed without a subquery.
D). This query will execute successfully. It filters rows based on the HIRE_DATE using a correct date format (assuming '9' refers to '09' or '1999' due to the NLS_DATE_FORMAT being 'DD-MON-RR'), then groups the remaining rows by DEPT_ID and calculates the sum of SALARY for each department.
E). This query will not execute successfully because it improperly nests MAX inside AVG without a subquery, and it incorrectly attempts to GROUP BY SALARY, which is already being aggregated.
References:
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "Aggregate Functions"
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "GROUP BY Clause"
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "HAVING Clause"

NEW QUESTION # 276
Examine this statement:

Which two statements are true?

A. The names of employees remaining the maximum salary will appear first in an ascending order
B. All remaining employee names will appear in descending order
C. All remaining employee names will appear in an ascending order
D. The names of employees maximum salary will appear fist to ascending order
E. The names of employees maximum salary will appear fist to descending order
F. All remaining employee names will appear in ascending order

Answer: E,F

NEW QUESTION # 277
View the Exhibit and examine the description of the EMPLOYEES table.

You want to calculate the total remuneration for each employee. Total remuneration is the sum of the annual salary and the percentage commission earned for a year. Only a few employees earn commission.
Which SQL statement would you execute to get the desired output?

A. SELECT first_name, salary, salary*12 + NVL(salary,0)*commission_pct, "Total"FROM EMPLOYEES;
B. SELECT first_name, salary (salary + NVL (commission_pct, 0)*salary)*12 "Total"FROM EMPLOYEES;
C. SELECT first_name, salary, salary*12+(salary*NVL2 (commission_pct,
salary,salary+commission_pct))"Total"FROM EMPLOYEES;
D. SELECT first_name, salary, salary*12+salary*commission_pct "Total"FROM EMPLOYEES;

Answer: C

NEW QUESTION # 278
......

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1z1-071 Study Plan, Reliable 1z1-071 Exam Book

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Oracle Database SQL Sample Questions (Q273-Q278):

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